125k^2-52=-7

Solution for 125k^2-52=-7 equation:

125k^2-52=-7

We move all terms to the left:

125k^2-52-(-7)=0

We add all the numbers together, and all the variables

125k^2-45=0

a = 125; b = 0; c = -45;
Δ = b2-4ac
Δ = 02-4·125·(-45)
Δ = 22500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{22500}=150$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-150}{2*125}=\frac{-150}{250}
=-3/5
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+150}{2*125}=\frac{150}{250}
=3/5
$